0=-16t^2+960

Solution for 0=-16t^2+960 equation:

0=-16t^2+960

We move all terms to the left:

0-(-16t^2+960)=0

We add all the numbers together, and all the variables

-(-16t^2+960)=0

We get rid of parentheses

16t^2-960=0

a = 16; b = 0; c = -960;
Δ = b2-4ac
Δ = 02-4·16·(-960)
Δ = 61440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{61440}=\sqrt{4096*15}=\sqrt{4096}*\sqrt{15}=64\sqrt{15}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{15}}{2*16}=\frac{0-64\sqrt{15}}{32}
=-\frac{64\sqrt{15}}{32}
=-2\sqrt{15}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{15}}{2*16}=\frac{0+64\sqrt{15}}{32}
=\frac{64\sqrt{15}}{32}
=2\sqrt{15}
$